官網題目敘述:
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:Given the below binary tree and
sum = 22
,
5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
過關時間:
這題算是簡單反正就找遍所有節點如果到末端剛好等於sum就回傳ture,這邊我用遞迴的方式去做,實際跑起來應該類似深度搜尋。
* Definition for a binary tree node. * function TreeNode(val) { * this.val = val; * this.left = this.right = null; * } */ /** * @param {TreeNode} root * @param {number} sum * @return {boolean} */ var hasPathSum = function(root, sum) { if(root===null)return false; sum-=root.val; if(sum===0 && (root.left===null && root.right===null))return true; return hasPathSum(root.left,sum) || hasPathSum(root.right,sum); }
文章標籤
全站熱搜
留言列表